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Hey all,

I decided to create a math quizzes that everyone on the forum can answer.

1) Let ABCD be a parallelogram where E is a point between AB such that 3BE = 2DC The lines CE and BD intersect at the point Q. If the area of <DQC is 36. Find the area of <BQE.

More to come...

It's not how good you are. It's how good you want to be - Paul Arden

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**ElainaVW****Member**- Registered: 2013-04-29
- Posts: 291

Hello:

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,215

Hi;

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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Yes, both of you are correct.

2) Let n and k be two positive integers such that k is less than n. It is know that (1+2+3+4+...+n)+k = 101. fFind k.

It's not how good you are. It's how good you want to be - Paul Arden

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,215

Hi;

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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Yes. Hmm...

3) Let 0 < y < 1. If A = y, B = y^2, C = 1/y and D = 1/y^2 arrange them from the largest to the smallest value.

How to do the message thing btw?

*Last edited by chooipian (2014-04-25 00:06:51)*

It's not how good you are. It's how good you want to be - Paul Arden

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,215

Hi;

You mean a hide message?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,215

Hi;

Use the hide tags.

and put what you want to hide between them. Yes I changed the order.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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4) Using only the numbers 1, 2, 3, 6, 7, 9, 0. Find which number goes with each of the letter in the addition problem below to make it correct. PAK = MAK = PIUT (I got this question for someone, I don't have a answer.)

5) Solve 200520062007^2 - 200520062006 x 200520062008 = (You are not allowed to use a calculator!)

That's all for now.

It's not how good you are. It's how good you want to be - Paul Arden

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,215

Hi;

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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