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You are not logged in. #1 20060227 21:51:50
AlgebraA # 1 Character is who you are when no one is looking. #2 20060228 00:03:01
Re: Algebrathe numbers are {3,4,5} IPBLE: Increasing Performance By Lowering Expectations. #4 20060228 02:11:00
Re: AlgebraThanks. IPBLE: Increasing Performance By Lowering Expectations. #5 20060302 03:20:33
Re: AlgebraA # 2 Character is who you are when no one is looking. #6 20060302 03:40:22
Re: Algebram=2? IPBLE: Increasing Performance By Lowering Expectations. #7 20060302 15:09:19
Re: Algebram=2 would have been better! The answer is m=2. Try again, krassi_holmz, probably you made a mistake somewhere. Character is who you are when no one is looking. #8 20060302 15:11:38
Re: AlgebraA # 3 Character is who you are when no one is looking. #9 20060302 19:28:39
Re: AlgebraA # 4 Character is who you are when no one is looking. #10 20060303 03:52:57
Re: AlgebraA # 3 Why did the vector cross the road? It wanted to be normal. #11 20060303 15:26:54
Re: AlgebraWell done, mathsyperson! Character is who you are when no one is looking. #12 20060303 16:29:28
Re: AlgebraA # 5 Character is who you are when no one is looking. #13 20060307 19:12:43
Re: AlgebraA # 6 Character is who you are when no one is looking. #14 20060309 15:15:28
Re: AlgebraA # 7 Character is who you are when no one is looking. #17 20060311 19:27:02
Re: Algebra(x^2+1/x^2)3(x1/x)2+22=0 then (x+1/x)^23(x1/x)4=0 if (x+1/x)=y y=4 and 1 now we solves (x+1/x)=4 and (x+1/x)=1 these equaition very easy #21 20101022 23:12:45
Re: AlgebraHi ganesh; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #24 20110214 00:06:44
Re: AlgebraHi soroban, Character is who you are when no one is looking. 