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## #1 2006-03-07 10:29:15

kaken
Guest

### Triangle

Hi! I was wondering.. how would you go into solving the perimeter and the area of this triangle with the data given. Thank you

## #2 2006-03-07 11:24:58

Dionysus
Member
Registered: 2006-03-06
Posts: 9

### Re: Triangle

I'm assuming H is the height, making H perpendicular to BC.
Therefore triangle abh is a right triangle, so by using pythagorean theorem,

:
144-81=63
Square root that to get 3√7 for B
You can do the same thing for the triangle on the right. adding
:
9 + 81 = 90
Simplify root 90 to get 3√10 for D

To find the area just find the base B + C = 3√7 + 3 and multiply it by your height of 9, and dividing by 2. The answer comes out to be exactly:

+

So to sum up, your appx area is 49.2176, and your apprx perimeter is 32.4241. If you need it exact, look above for the radicals. (All in feet)

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## #3 2006-03-07 13:44:29

kaken
Guest

### Re: Triangle

Dionysus wrote:

I'm assuming H is the height, making H perpendicular to BC.
Therefore triangle abh is a right triangle, so by using pythagorean theorem,

:
144-81=63
Square root that to get 3√7 for B
You can do the same thing for the triangle on the right. adding
:
9 + 81 = 90
Simplify root 90 to get 3√10 for D

To find the area just find the base B + C = 3√7 + 3 and multiply it by your height of 9, and dividing by 2. The answer comes out to be exactly:

+

So to sum up, your appx area is 49.2176, and your apprx perimeter is 32.4241. If you need it exact, look above for the radicals. (All in feet)

Oh! I see what you mean.. Thanks!

## #4 2006-03-07 18:48:03

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,905

### Re: Triangle

Well done, Dionysus!
Very good!

IPBLE:  Increasing Performance By Lowering Expectations.

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## #5 2006-03-08 01:05:56

Dionysus
Member
Registered: 2006-03-06
Posts: 9

Thank You

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