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#1 2006-03-08 09:29:15

kaken
Guest

Triangle

Hi! I was wondering.. how would you go into solving the perimeter and the area of this triangle with the data given. Thank you

#2 2006-03-08 10:24:58

Dionysus
Novice

Offline

Re: Triangle

I'm assuming H is the height, making H perpendicular to BC.
Therefore triangle abh is a right triangle, so by using pythagorean theorem,

:
144-81=63
Square root that to get 3√7 for B
You can do the same thing for the triangle on the right. adding
:
9 + 81 = 90
Simplify root 90 to get 3√10 for D

To find the area just find the base B + C = 3√7 + 3 and multiply it by your height of 9, and dividing by 2. The answer comes out to be exactly:
+

So to sum up, your appx area is 49.2176, and your apprx perimeter is 32.4241. If you need it exact, look above for the radicals. (All in feet)

#3 2006-03-08 12:44:29

kaken
Guest

Re: Triangle

Dionysus wrote:

I'm assuming H is the height, making H perpendicular to BC.
Therefore triangle abh is a right triangle, so by using pythagorean theorem,

:
144-81=63
Square root that to get 3√7 for B
You can do the same thing for the triangle on the right. adding
:
9 + 81 = 90
Simplify root 90 to get 3√10 for D

To find the area just find the base B + C = 3√7 + 3 and multiply it by your height of 9, and dividing by 2. The answer comes out to be exactly:
+

So to sum up, your appx area is 49.2176, and your apprx perimeter is 32.4241. If you need it exact, look above for the radicals. (All in feet)

Oh! I see what you mean.. Thanks!

#4 2006-03-08 17:48:03

krassi_holmz
Real Member

Offline

Re: Triangle

Well done, Dionysus!
Very good!

IPBLE:  Increasing Performance By Lowering Expectations.

Dionysus
Novice

Offline

Thank You