Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

Login

Username

Password

Not registered yet?

  • Index
  •  » Help Me !
  •  » √1+(√2+(√3+(√4+... = ? Harder than it seems

#26 2013-11-23 12:37:57

bobbym
Administrator

Online

Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Depends on how you interpret a result like that.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#27 2013-11-23 12:41:50

anonimnystefy
Real Member

Offline

Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

I do not understand what you have against him, exactly. Could you explain?


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#28 2013-11-23 12:48:06

bobbym
Administrator

Online

Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Against whom? The i guy or Borwein?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#29 2013-11-23 12:48:49

anonimnystefy
Real Member

Offline

Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Both.


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#30 2013-11-23 12:51:51

bobbym
Administrator

Online

Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Nothing against either Borwein, they are brilliant guys.

The i guy used it as an excuse for not doing numerical work.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#31 2013-12-15 14:55:18

George,Y
Super Member

Offline

Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Actually, the answer is 3
Look at this poster before 2013 Asian Football Championship, the score will be 3:0
http://img4.cache.netease.com/photo/0005/2013-11-04/9CRN7PE44FFD0005.jpg


X'(y-Xβ)=0

#32 2013-12-15 14:56:20

George,Y
Super Member

Offline

Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Oops, I post the wrong question


X'(y-Xβ)=0

#33 2013-12-15 18:13:44

bobbym
Administrator

Online

Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Hi;

Yes, that is a different problem.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
  • Index
  •  » Help Me !
  •  » √1+(√2+(√3+(√4+... = ? Harder than it seems

Board footer

Powered by FluxBB