Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

• Index
•  » Help Me !
•  » √1+(√2+(√3+(√4+... = ? Harder than it seems

## #26 2013-11-23 12:37:57

bobbym

Offline

### Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Depends on how you interpret a result like that.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #27 2013-11-23 12:41:50

anonimnystefy
Real Member

Offline

### Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

I do not understand what you have against him, exactly. Could you explain?

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #28 2013-11-23 12:48:06

bobbym

Offline

### Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Against whom? The i guy or Borwein?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #29 2013-11-23 12:48:49

anonimnystefy
Real Member

Offline

### Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Both.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #30 2013-11-23 12:51:51

bobbym

Offline

### Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Nothing against either Borwein, they are brilliant guys.

The i guy used it as an excuse for not doing numerical work.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #31 2013-12-15 14:55:18

George,Y
Super Member

Offline

### Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Look at this poster before 2013 Asian Football Championship, the score will be 3:0

X'(y-Xβ)=0

## #32 2013-12-15 14:56:20

George,Y
Super Member

Offline

### Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Oops, I post the wrong question

X'(y-Xβ)=0

## #33 2013-12-15 18:13:44

bobbym

Offline

### Re: √1+(√2+(√3+(√4+... = ? Harder than it seems

Hi;

Yes, that is a different problem.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
• Index
•  » Help Me !
•  » √1+(√2+(√3+(√4+... = ? Harder than it seems