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#1 2013-12-09 23:21:34

Registered: 2013-12-09
Posts: 4

another odds ratio case

in online game, two team fight against each other

team a   strength  73% ,which corespond to 100% (for conveniece, here note 73)
team b   strenth   46

then odds ratio =73/(100-73)/ (46/(100-46)=73/27/(45/55)
no problem here

suppose team;s strength divided into two part  attck and defense
team a  attack=44    defense=6
team b  attack=64    defense=33
where 100 correspoinds to the best rank

in odds ratio formula, winthin a group ,  p,  100-p

since attack+defense is not equal to 100, which puzzled me.
I use several method,

for conveniece
team a attack note m
team a defense n
team b attck o
team b defense p

method 1
strenth=(attack +defense)/2   algebra average value
then use the fumula of odds ratio
odds ratio=((m+n)/2)(100-(m+n)/2)/ ( ((o+p)/2)/(100-((o+p)/2)))

method 2
strength=sqrt((attack +defense) geometry average value

methd 3
regard defense is unlike probilities,juse use odds ratio formula directly
odds ratio=m/p /(o/n)

method 4 

odds ratio= m/(100-m)/(p/(100-p))/  (o/(100-o)/(n/(100-n)))

method XX

which is right? or they were all wrong ? any solution pls give me help?

how to calculate odds ratio?

Last edited by extjsjquery (2013-12-09 23:43:56)


#2 2013-12-10 01:47:44

From: Bumpkinland
Registered: 2009-04-12
Posts: 105,294

Re: another odds ratio case


I am not sure what you are trying to do here. The OR as far as I know is finding the correlation between binary data. How does what you are doing relate to that?

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
No great discovery was ever made without a bold guess.


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