in online game, two team fight against each other
team a strength 73% ,which corespond to 100% (for conveniece, here note 73)
team b strenth 46
then odds ratio =73/(100-73)/ (46/(100-46)=73/27/(45/55)
no problem here
suppose team;s strength divided into two part attck and defense
team a attack=44 defense=6
team b attack=64 defense=33
where 100 correspoinds to the best rank
in odds ratio formula, winthin a group , p, 100-p
since attack+defense is not equal to 100, which puzzled me.
I use several method,
team a attack note m
team a defense n
team b attck o
team b defense p
strenth=(attack +defense)/2 algebra average value
then use the fumula of odds ratio
odds ratio=((m+n)/2)(100-(m+n)/2)/ ( ((o+p)/2)/(100-((o+p)/2)))
strength=sqrt((attack +defense) geometry average value
regard defense is unlike probilities,juse use odds ratio formula directly
odds ratio=m/p /(o/n)
odds ratio= m/(100-m)/(p/(100-p))/ (o/(100-o)/(n/(100-n)))
which is right? or they were all wrong ? any solution pls give me help?
how to calculate odds ratio?
Last edited by extjsjquery (2013-12-09 23:43:56)
I am not sure what you are trying to do here. The OR as far as I know is finding the correlation between binary data. How does what you are doing relate to that?
If it ain't broke, fix it until it is.
A number by itself is useful, but it is far more useful to know how accurate or certain that number is.