Hi this is my first post here.
On the puzzle ABCD × E = DCBA
Should it not be, (A)(B)(C)(D) x E = (D)(C)(B)(A)
There for A, B, C, D can be anything as long as E = 1 or 0?
If this has been discussed before sorry.
Last edited by dford (2013-12-06 17:04:33)
(A)(B) is like (2)(4), which would mean 2x4.
AB is like 24
So if A =2, B = , C = , D = 8, and E = 4, then
"Who Dares Wins" - Motto of the British Special Air Service
Another solution is 1089 * 9 = 9801 provided there is no condition that all the numbers have to be different.
If it ain't broke, fix it until it is.
A number by itself is useful, but it is far more useful to know how accurate or certain that number is.