Hi this is my first post here.
On the puzzle ABCD × E = DCBA
Should it not be, (A)(B)(C)(D) x E = (D)(C)(B)(A)
There for A, B, C, D can be anything as long as E = 1 or 0?
If this has been discussed before sorry.
Last edited by dford (2013-12-06 17:04:33)
(A)(B) is like (2)(4), which would mean 2x4.
AB is like 24
So if A =2, B = , C = , D = 8, and E = 4, then
Another solution is 1089 * 9 = 9801 provided there is no condition that all the numbers have to be different.
In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.