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You are not logged in. #1876 20130820 12:24:00
Re: Is this cool with you?Hi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1877 20130820 17:14:57
Re: Is this cool with you?Hi; The sum that generates the coefficients is: Where balls = total number of balls urn = number of urns max = maximum number of balls in any urn. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1878 20130820 21:13:29
Re: Is this cool with you?Have you tested it? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1879 20130820 21:20:56
Re: Is this cool with you?Oh, and, a general formula for the line and squares problem: The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1880 20130820 22:01:49
Re: Is this cool with you?I have tested it a great deal it will produce the coefficients of the gf. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1881 20130928 05:24:00
Re: Is this cool with you?
I have this , but I don't how much faster it is...The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1882 20130928 06:14:46
Re: Is this cool with you?Hi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1883 20130928 06:19:45
Re: Is this cool with you?Hi bobbym Last edited by anonimnystefy (20130928 06:19:58) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1884 20130928 06:27:35
Re: Is this cool with you?There are many other methods besides RRA. In addition, any series can be converted into an alternating one and then RRA or Euler applied. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1885 20130928 06:46:10
Re: Is this cool with you?Which is in turn , so it's 1/k^5 rate of convergence!The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1886 20130928 06:49:32
Re: Is this cool with you?That is true and the whole point but you had to see a trick first... In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1887 20130928 06:51:46
Re: Is this cool with you?Which trick? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1888 20130928 06:53:11
Re: Is this cool with you?The trick is how to sum that else you have replaced one cubic convergence with another. Do you see it? In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1889 20130928 07:06:15
Re: Is this cool with you?I do. Partial fractions and telescoping. It is what the page I found used. http://mathworld.wolfram.com/Convergenc … ement.html The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1890 20130928 07:14:42
Re: Is this cool with you?So you are only left with the sum on the extreme right and it has much faster convergence. Now you should numerically verify that. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1891 20130928 07:24:11
Re: Is this cool with you?Hi bobbym The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1892 20130928 07:28:35
Re: Is this cool with you?Which sum do you want to do? In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1893 20130928 07:29:59
Re: Is this cool with you?All mentioned so far, starting with the first one (sum of 1/k^3)... The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1894 20130928 07:33:51
Re: Is this cool with you?Corny questions that come up in math courses which ask how many terms you need are replaced by what does the sum converge to and to how many digits can we get. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1895 20130928 07:36:43
Re: Is this cool with you?That does not answer my question of how to actually get the number of needed terms... The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1896 20130928 07:43:04
Re: Is this cool with you?I am not following you. It is a computational problem. To get the terms you have to use a computer and add them up. Then you need a tail analysis, remember most of the time you do not know what the sum is. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1897 20130928 07:52:03
Re: Is this cool with you?But, in the original problem, you said we need 80000 terms. How did you get that number? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1898 20130928 07:54:45
Re: Is this cool with you?There are a couple of easy ways to back that statement up.First and simplest rule of thumb is the double rule. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #1899 20130928 07:57:58
Re: Is this cool with you?Give me something concrete, please. I still haven't the slightest how to get that estimate. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #1900 20130928 08:01:39
Re: Is this cool with you?We can use the simplest command in M. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 