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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

Simplify the following, leaving your answer in standard form.

I have solved it but had different solution from what the book has, I need some assistance.

1) 0.81 * 10^-5/2.25 * 10

2). 0.0048 * 0.81 * 10^-7/ 0.027 * 0.04 * 10^6

Both number one and two are in a 'square root sign'

Please, I would be much obliged if you produce your steps here.

Thanks in advance.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

What were your answers?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

1). I had 6.0 * 10^-15

And

2). I had, 6.0 * 10^-9.

*Last edited by EbenezerSon (2013-08-11 22:09:07)*

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

Okay, 1) looks like this?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

Yes. But all are in a square root.

Sorry! the denominator is 2.25 * 10^7

Forgive me.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

So we have:

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

Right!

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

You were close I am getting 6 x 10^-7

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

Please can you provide the steps?

Thanks.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

Do it by pieces, what is

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

= 10^(-5-7)=10^-12.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

Very good.

Now what is .81 / 2.25?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

= 0.36 *10^0

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

Leave out the 10^0, it is 1. We do not show multiplication by 1.

Now combine the two answers.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

0.36 * 10-12

= 0.6 * 10^-6

= 6.0 * 10^-7

It looks I was confused by the root.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

Very good. It is awful making a human being do such calculations. We have machinery for that nowadays.

Is this 2)?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

Yes, Bobbym.

I just want to become used to them, cos in no time I will be teaching others.

Now, I had the same answer for the second question.

I owe you some thanks. :-)

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

That book has a sense of humor at least. I am getting the same answer as 1).

I owe you some thanks. :-)

No thanks required.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

Yes I tried to solve it once again and now I have the same answer as the first one, The root was my main problem, but now I have known how to go about that.

Thank you very much Bobbym.

God bless you!

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

Hi;

You are welcome. I am going to take a break, see you in a bit.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 464

Okay.

I will return getting to nıght time.

I know only one thing - that is that I know nothing

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,735

Hi;

Sorry for the delay but I needed an hour or so nap.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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