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## #276 2013-08-11 05:56:21

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

Now I have learnt that! Thanks much Bobbym!

Okay, back to my question.

27^(n+2) =27^n * 27^2 =  3^(3n) * 3^(6)
.

Why didn't you use  3^(3n) * 3^(6) but rather wrote 9^(n+2) * 3^(n+2).

I know only one thing - that is that I know nothing

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## #277 2013-08-11 06:05:41

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

All that is correct.

Why didn't you use  3^(3n) * 3^(6) but rather wrote 9^(n+2) * 3^(n+2).

Because it was easier to cancel.

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #278 2013-08-11 06:38:43

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

Candidly speaking, since I started working on indices I haven't seen nor come accros a problem that could produce different bases as your own. As you made 9^(n+2) *3^(n+2) out of 27^(n+2)

Now I think the method that will be applicable to a problem is the one that must be used.

Thank very much Bobbym, God bless you.

I know only one thing - that is that I know nothing

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## #279 2013-08-11 10:10:19

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

Hi;

Glad to help and let me know when you need more.

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #280 2014-08-22 22:03:54

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

bobbym wrote:

Okay, I will provide the steps:

Take the log of both sides.

Divide both sides by ( log(2) + log(3) ).

And we are done.

Hi

thanks

I know only one thing - that is that I know nothing

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## #281 2014-08-22 22:14:29

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

Hi;

Line 2?

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #282 2014-08-22 22:16:04

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

Besides, there was two 'x' as in xlog3 + xlog2, And you didn't add those two x to be '2x', or in other words, why didn't you add those x's to be 2x after you divided log2 by log3 + log2, do you understand my question?

I know only one thing - that is that I know nothing

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## #283 2014-08-22 22:17:25

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

bobbym wrote:

Hi;

Line 2?

yes

I know only one thing - that is that I know nothing

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## #284 2014-08-22 22:27:51

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

The general rule:

Log(ab) = Log(a) + Log(b)

Under certain conditions of course.

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #285 2014-08-22 22:55:57

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

I know only one thing - that is that I know nothing

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## #286 2014-08-22 23:14:38

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

Besides, there was two 'x' as in xlog3 + xlog2, And you didn't add those two x to be '2x', or in other words, why didn't you add those x's to be 2x after you divided log2 by log3 + log2, do you understand my question?

Please, what line do you mean?

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #287 2014-08-23 05:37:39

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

See line 4, there is one 'x'  behind log2 and another 'x' behind log3, why didn't you add those xs so that it would have been 2x.

x( y^1/2 - x^1/2)
= (xy^3/2 - x^3/2)

I know only one thing - that is that I know nothing

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## #288 2014-08-23 12:57:04

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

Hi;

I am afraid that

x log(2) + x  log(3) does not allow us to add the x's and say 2x.

x( y^1/2 - x^1/2)
= (xy^3/2 - x^3/2)

That is not correct, please try again.

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #289 2014-08-24 04:16:19

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

I think you want me to say; (xy^1/2 - x^1/2)
But I have in mind that the 'x'(the x which is outside of bracket) is raising to the power 1, but the 1 is not clearly written and that I am thinking my answer at 287 is correct, what do you say?

Last edited by EbenezerSon (2014-08-24 04:17:39)

I know only one thing - that is that I know nothing

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## #290 2014-08-24 04:50:18

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

Hi;

I think you want me to say; (xy^1/2 - x^1/2)

Not exactly, that is incorrect also. You are correct in stating that x is x^1. Now just go through it piece by piece adding the exponents of x.

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #291 2014-08-24 08:22:14

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

I have done that, still I only arrive at the same answer.

I know only one thing - that is that I know nothing

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## #292 2014-08-24 21:51:34

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

Hi;

What is x( y^1/2 )?

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #293 2014-08-26 09:45:28

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

To begin with I would say the X instrinsically raised to the power positive one[1], so I will say 1+1/2 = 3/2.  Therefore;
XY^3/2

I know only one thing - that is that I know nothing

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## #294 2014-08-26 21:16:00

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

But there is no x in there. x^1 = x. What you have is x^0 = 1.

So x( y^1/2 ) = x y^1/2

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #295 2014-08-27 03:35:23

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

I was talking of the X which is outside the bracket. Look at a similar case at #182 line one, after you had multiplied 2^-x through,  the 2 at right side became 2^x+1, this indicates that the 2 already had 1 as its power, and in this problem  I perceive that the X has 1 as its power though not visibly expressed or written , what do  you say?
Thanks

I know only one thing - that is that I know nothing

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## #296 2014-08-27 03:40:17

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

In the parentheses of x( y^1/2 ), there is only a y to the (1/2) power. There is no x in there other than x^0 which equals 1 so we do not include it.

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #297 2014-08-27 03:51:09

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

So,  if there was X in the bracket  having 1/2 as it power how would the answer be? like x(y^1/2 - x^1/2)

Thank you.

Last edited by EbenezerSon (2014-08-27 04:00:48)

I know only one thing - that is that I know nothing

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## #298 2014-08-27 04:08:24

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

For x(y^1/2 - x^1/2)

you do the first term first:

then the second term:

because you add the exponents which are 1 and 1 / 2 = 3 / 2.

Then you finish off by combining the two terms.

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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## #299 2014-08-27 04:47:48

EbenezerSon
Member
Registered: 2013-07-04
Posts: 473

### Re: Simplify the following:

Why did you not say x(y^1/2) = xy^3/2 I think the x has 1 as its power, please I am not getting you with this x(y^1/2) = xy^1/2. Please explicate.

Last edited by EbenezerSon (2014-08-27 04:49:50)

I know only one thing - that is that I know nothing

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## #300 2014-08-27 04:56:47

bobbym
From: Bumpkinland
Registered: 2009-04-12
Posts: 90,562

### Re: Simplify the following:

Hi;

You can only add the exponents when the bases are the same:

both are x's so add the exponents.

both are y's so add the exponents.

, it just stays the same. You can do nothing here because the x and y are different.

In mathematics, you don't understand things. You just get used to them.

I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.

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