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## #276 2013-08-11 05:56:21

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

Now I have learnt that! Thanks much Bobbym!

Okay, back to my question.

27^(n+2) =27^n * 27^2 =  3^(3n) * 3^(6)
.

Why didn't you use  3^(3n) * 3^(6) but rather wrote 9^(n+2) * 3^(n+2).

I know only one thing - that is that I know nothing

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## #277 2013-08-11 06:05:41

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

All that is correct.

Why didn't you use  3^(3n) * 3^(6) but rather wrote 9^(n+2) * 3^(n+2).

Because it was easier to cancel.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #278 2013-08-11 06:38:43

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

Candidly speaking, since I started working on indices I haven't seen nor come accros a problem that could produce different bases as your own. As you made 9^(n+2) *3^(n+2) out of 27^(n+2)

Now I think the method that will be applicable to a problem is the one that must be used.

Thank very much Bobbym, God bless you.

I know only one thing - that is that I know nothing

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## #279 2013-08-11 10:10:19

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

Hi;

Glad to help and let me know when you need more.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #280 2014-08-22 22:03:54

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

bobbym wrote:

Okay, I will provide the steps:

Take the log of both sides.

Add log(2) to both sides.

Divide both sides by ( log(2) + log(3) ).

And we are done.

Hi

Initially there was no addition sign[+] but in the course of manipulation you happen to bring an addition sign instead of the multiplication sign.
thanks

I know only one thing - that is that I know nothing

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## #281 2014-08-22 22:14:29

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

Hi;

Line 2?

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #282 2014-08-22 22:16:04

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

Besides, there was two 'x' as in xlog3 + xlog2, And you didn't add those two x to be '2x', or in other words, why didn't you add those x's to be 2x after you divided log2 by log3 + log2, do you understand my question?

I know only one thing - that is that I know nothing

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## #283 2014-08-22 22:17:25

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

bobbym wrote:

Hi;

Line 2?

yes

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## #284 2014-08-22 22:27:51

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

The general rule:

Log(ab) = Log(a) + Log(b)

Under certain conditions of course.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #285 2014-08-22 22:55:57

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

Please answer my question at #282,  if it is unintelligible please tell me

I know only one thing - that is that I know nothing

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## #286 2014-08-22 23:14:38

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

Besides, there was two 'x' as in xlog3 + xlog2, And you didn't add those two x to be '2x', or in other words, why didn't you add those x's to be 2x after you divided log2 by log3 + log2, do you understand my question?

Please, what line do you mean?

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #287 2014-08-23 05:37:39

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

See line 4, there is one 'x'  behind log2 and another 'x' behind log3, why didn't you add those xs so that it would have been 2x.

Please check these for me:

x( y^1/2 - x^1/2)
= (xy^3/2 - x^3/2)
Is my answer correct?

I know only one thing - that is that I know nothing

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## #288 2014-08-23 12:57:04

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

Hi;

I am afraid that

x log(2) + x  log(3) does not allow us to add the x's and say 2x.

x( y^1/2 - x^1/2)
= (xy^3/2 - x^3/2)
Is my answer correct?

That is not correct, please try again.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #289 2014-08-24 04:16:19

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

I think you want me to say; (xy^1/2 - x^1/2)
But I have in mind that the 'x'(the x which is outside of bracket) is raising to the power 1, but the 1 is not clearly written and that I am thinking my answer at 287 is correct, what do you say?

Last edited by EbenezerSon (2014-08-24 04:17:39)

I know only one thing - that is that I know nothing

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## #290 2014-08-24 04:50:18

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

Hi;

I think you want me to say; (xy^1/2 - x^1/2)

Not exactly, that is incorrect also. You are correct in stating that x is x^1. Now just go through it piece by piece adding the exponents of x.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #291 2014-08-24 08:22:14

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

I have done that, still I only arrive at the same answer.

I know only one thing - that is that I know nothing

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## #292 2014-08-24 21:51:34

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

Hi;

What is x( y^1/2 )?

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #293 2014-08-26 09:45:28

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

To begin with I would say the X instrinsically raised to the power positive one[1], so I will say 1+1/2 = 3/2.  Therefore;
XY^3/2

I know only one thing - that is that I know nothing

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## #294 2014-08-26 21:16:00

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

But there is no x in there. x^1 = x. What you have is x^0 = 1.

So x( y^1/2 ) = x y^1/2

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #295 2014-08-27 03:35:23

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

I was talking of the X which is outside the bracket. Look at a similar case at #182 line one, after you had multiplied 2^-x through,  the 2 at right side became 2^x+1, this indicates that the 2 already had 1 as its power, and in this problem  I perceive that the X has 1 as its power though not visibly expressed or written , what do  you say?
Thanks

I know only one thing - that is that I know nothing

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## #296 2014-08-27 03:40:17

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

In the parentheses of x( y^1/2 ), there is only a y to the (1/2) power. There is no x in there other than x^0 which equals 1 so we do not include it.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #297 2014-08-27 03:51:09

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

So,  if there was X in the bracket  having 1/2 as it power how would the answer be? like x(y^1/2 - x^1/2)

Thank you.

Last edited by EbenezerSon (2014-08-27 04:00:48)

I know only one thing - that is that I know nothing

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## #298 2014-08-27 04:08:24

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

For x(y^1/2 - x^1/2)

you do the first term first:

then the second term:

because you add the exponents which are 1 and 1 / 2 = 3 / 2.

Then you finish off by combining the two terms.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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## #299 2014-08-27 04:47:48

EbenezerSon
Member
Registered: 2013-07-04
Posts: 551

### Re: Simplify the following:

Why did you not say x(y^1/2) = xy^3/2 I think the x has 1 as its power, please I am not getting you with this x(y^1/2) = xy^1/2. Please explicate.

Last edited by EbenezerSon (2014-08-27 04:49:50)

I know only one thing - that is that I know nothing

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## #300 2014-08-27 04:56:47

bobbym
bumpkin
From: Bumpkinland
Registered: 2009-04-12
Posts: 109,606

### Re: Simplify the following:

Hi;

You can only add the exponents when the bases are the same:

both are x's so add the exponents.

both are y's so add the exponents.

, it just stays the same. You can do nothing here because the x and y are different.

In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

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