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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 242

Make k the subject.

1/n = (k^+p^2/hg)^1/2

I have k=(hg/n^2-p^2) as the answer. But the book solved beyond my final solution, and even had negative or positive sign in it.

please help me understand why its had that final answer, and as well how it came by the negative or positive sign.

Thanks in advance.

This is its final answer;

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 82,724

Hi;

What comes after the k^?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,259

Is this your starting point?

If not, please modify this Latex so we know what the question is.

Thanks,

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,860

I'd say it's:

Or maybe with k and p both in the denominator.

*Last edited by anonimnystefy (2013-08-04 10:40:32)*

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,259

hi Stefy,

I'm sure you are right so here goes:

Ebenezerson: That looks a bit like what you had. **But k is not yet the subject. ** We must deal with the square root:

Hope that is what you were wanting.

note:

You must not just invert all the fractions to get

Try with numbers:

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 242

The 'k' squared plus the 'p' squared are on one platform, which is over the 'hg'.

And all of them are in a square root sign.

Thanks.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 242

bobbym wrote:

Hi;

What comes after the k^?

"equal to sign" and after the sign, there is a "negative or positive sign" which confound me much.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 82,724

I am curious, which answer did you like?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 242

EbenezerSon wrote:

Make k the subject.

I had, k=(hg/n^2-p^2)

But the book has 1/n and a negative or positive sign after the "equl to sign", which is incomprehensible to me. Some help.

Please solve it and you will definitly come across what I mean.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 82,724

Is post #4 the right problem?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 242

No.

the k squared plus the p squared are on one platform, all over "hg". That's all,

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 82,724

Hi;

Have you considered using codecogs? Then you would be able to latex the problem.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,860

I'd say this is the problem:

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 242

Bobbym, I cant found them at the bottom of the open window. There are few that are found there.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 82,724

Is post #13 the form you want?

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 242

Yes, correcto perfecto.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 82,724

Hi;

The correct answers are:

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 242

the 'n' at the bottom carries a square why didnt you bring it?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 82,724

Sorry, I am not getting an n^2 just an n. I had Mathematica do that and he is never wrong.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**EbenezerSon****Member**- Registered: 2013-07-04
- Posts: 242

If we take it from the start. the n has to be squared when the square root at the R.H is taking away.

By the way what is mathematica I am curious to know.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,860

But, when you clear k of the square, you will be taking a square root, which means n will lose the square.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 82,724

Yes, the n^2 will disappear.

Mathematica is a computer program that is smarter than 1001 mathematicians.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,259

square both sides

times hg

subtract p squared

square root

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,259

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,259

bobbym wrote:

Mathematica is a computer program that is smarter than 1001 mathematicians.

But just those 1001. The rest of the mathematicians are still smarter.

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