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#1 2013-07-04 11:03:57

EbenezerSon
Member
Registered: 2013-07-04
Posts: 456

Algebraic problem.

Hello sir, please assist me to solve these algebra.

x+x+x2-x2.  please the two x are squared, I cannot locate them(the squares) in this forum in order to apply them  conveniently on them.


I know only one thing - that is that I know nothing

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#2 2013-07-04 13:06:13

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,302

Re: Algebraic problem.

Hi EbenezerSon;

Welcome to the forum.

This looks like what you want done:

x + x = 2x

2x + x^2 = 2x + x^2

Now x^2 - x^2 = 0.

2x + 0 = 2x


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#3 2013-07-05 03:57:54

EbenezerSon
Member
Registered: 2013-07-04
Posts: 456

Re: Algebraic problem.

Thank you sir, God bless, but please one more problem from algebra.
1. (h^2 - h^2) -p(h + h).

2. X^2 + X^2 + X^2 - Y^2


Please, where can I use the mathematical items, like the (square), (plus symbol) and the others in this forum, as  you have used them nicely above.

Thanks.


I know only one thing - that is that I know nothing

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#4 2013-07-05 04:32:32

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,302

Re: Algebraic problem.

You can use latex, that is what I am using. It is all done by a site. Take a look here.

http://latex.codecogs.com/editor.php

1) (h^2 - h^2) -p(h + h)

h^2 - h^2 is 0

0  - p(h + h)

Can you do the next step?

2)  X^2 + X^2 + X^2 - Y^2

X^2 + X^2 + X^2  is 3X^2

3X^2 - Y^2 we can not simplfy any further so you are done.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#5 2013-07-05 10:38:38

EbenezerSon
Member
Registered: 2013-07-04
Posts: 456

Re: Algebraic problem.

0-p(h + h)
= -hp - hp.


I know only one thing - that is that I know nothing

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#6 2013-07-05 10:44:02

EbenezerSon
Member
Registered: 2013-07-04
Posts: 456

Re: Algebraic problem.

But sir, the book in which I am learning this from has given me a different answer altogether.

It is saying, though an algebra but this type of question is called "difference of two squares".

I would provide his procedure here, which I could not quite comprehend some aspects of his proceduredizzy.


I really appreciate your enormous assistance.

Thanks.

Last edited by EbenezerSon (2013-07-05 10:50:17)


I know only one thing - that is that I know nothing

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#7 2013-07-05 14:08:08

ShivamS
Member
Registered: 2011-02-07
Posts: 3,530

Re: Algebraic problem.

Hi, if you want to simplify  0-p (h+h), it would be ph + ph which  is 2ph. Secondly, difference of two squares implies that you need to factor these, not just simplify. To do that, you must use the identity (a^2)-(a^2) equals (a+b)(a-b).  smile

Last edited by Shivamcoder3013 (2013-07-05 14:09:40)

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#8 2013-07-05 14:21:23

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,302

Re: Algebraic problem.

But how can you factor them?

1) (h^2 - h^2) -p(h + h)

h^2 - h^2 = 0

There is no difference of 2 squares.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#9 2013-07-05 23:48:40

{7/3}
Member
Registered: 2013-02-11
Posts: 210

Re: Algebraic problem.

Ebenezerson I think u are posting wrong question


There are 10 kinds of people in the world,people who understand binary and people who don't.

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#10 2013-07-08 02:12:39

EbenezerSon
Member
Registered: 2013-07-04
Posts: 456

Re: Algebraic problem.

Regarding the problem above I think the member omitted the 'negative sign'.

The following is how I see it;

0-p(h+h) = (-ph - ph)

= -2ph , What do you say with my solution? The 'negative sign' was affecting the P.


I know only one thing - that is that I know nothing

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#11 2013-07-08 02:20:46

EbenezerSon
Member
Registered: 2013-07-04
Posts: 456

Re: Algebraic problem.

(h^2  -  h^2) -p(h+h)

= (h - h)(h + h) -p(h+h)

= (h + h)(h - h - p) . The final solution provided by the book.kiss

Last edited by EbenezerSon (2013-07-08 02:23:57)


I know only one thing - that is that I know nothing

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#12 2013-07-08 02:26:09

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,302

Re: Algebraic problem.

Hi;

That is an extremely weird answer they give.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#13 2013-07-08 02:33:55

EbenezerSon
Member
Registered: 2013-07-04
Posts: 456

Re: Algebraic problem.

bobbym wrote:

Hi;

That is an extremely weird answer they give.

Sir, forgive me I should have provided how the question should be solved. the question says:

(The factorize the expression completely). I think it should be the answer if we are to factorize it,  I have now comprehended it.  And I can explain.

What do you say.

Last edited by EbenezerSon (2013-07-08 02:35:24)


I know only one thing - that is that I know nothing

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#14 2013-07-08 02:41:06

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,302

Re: Algebraic problem.

Hi;

If you now understand what they did then that is okay with me.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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