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#1 2013-07-05 09:03:57

EbenezerSon
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Algebraic problem.

Hello sir, please assist me to solve these algebra.

x+x+x2-x2.  please the two x are squared, I cannot locate them(the squares) in this forum in order to apply them  conveniently on them.

#2 2013-07-05 11:06:13

bobbym
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Re: Algebraic problem.

Hi EbenezerSon;

Welcome to the forum.

This looks like what you want done:



x + x = 2x



2x + x^2 = 2x + x^2



Now x^2 - x^2 = 0.



2x + 0 = 2x


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#3 2013-07-06 01:57:54

EbenezerSon
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Re: Algebraic problem.

Thank you sir, God bless, but please one more problem from algebra.
1. (h^2 - h^2) -p(h + h).

2. X^2 + X^2 + X^2 - Y^2


Please, where can I use the mathematical items, like the (square), (plus symbol) and the others in this forum, as  you have used them nicely above.

Thanks.

#4 2013-07-06 02:32:32

bobbym
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Re: Algebraic problem.

You can use latex, that is what I am using. It is all done by a site. Take a look here.

http://latex.codecogs.com/editor.php

1) (h^2 - h^2) -p(h + h)

h^2 - h^2 is 0

0  - p(h + h)

Can you do the next step?

2)  X^2 + X^2 + X^2 - Y^2

X^2 + X^2 + X^2  is 3X^2

3X^2 - Y^2 we can not simplfy any further so you are done.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#5 2013-07-06 08:38:38

EbenezerSon
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Re: Algebraic problem.

0-p(h + h)
= -hp - hp.

#6 2013-07-06 08:44:02

EbenezerSon
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Re: Algebraic problem.

But sir, the book in which I am learning this from has given me a different answer altogether.

It is saying, though an algebra but this type of question is called "difference of two squares".

I would provide his procedure here, which I could not quite comprehend some aspects of his proceduredizzy.


I really appreciate your enormous assistance.

Thanks.

Last edited by EbenezerSon (2013-07-06 08:50:17)

#7 2013-07-06 12:08:08

ShivamS
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Re: Algebraic problem.

Hi, if you want to simplify  0-p (h+h), it would be ph + ph which  is 2ph. Secondly, difference of two squares implies that you need to factor these, not just simplify. To do that, you must use the identity (a^2)-(a^2) equals (a+b)(a-b).  smile

Last edited by Shivamcoder3013 (2013-07-06 12:09:40)


I have discovered a truly marvellous signature, which this margin is too narrow to contain. -Fermat
Give me a lever long enough and a fulcrum on which to place it, and I shall move the world. -Archimedes
Young man, in mathematics you don't understand things. You just get used to them. - Neumann

#8 2013-07-06 12:21:23

bobbym
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Re: Algebraic problem.

But how can you factor them?

1) (h^2 - h^2) -p(h + h)

h^2 - h^2 = 0

There is no difference of 2 squares.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#9 2013-07-06 21:48:40

{7/3}
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Re: Algebraic problem.

Ebenezerson I think u are posting wrong question


There are 10 kinds of people in the world,people who understand binary and people who don't.

#10 2013-07-09 00:12:39

EbenezerSon
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Re: Algebraic problem.

Regarding the problem above I think the member omitted the 'negative sign'.

The following is how I see it;

0-p(h+h) = (-ph - ph)

= -2ph , What do you say with my solution? The 'negative sign' was affecting the P.

#11 2013-07-09 00:20:46

EbenezerSon
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Re: Algebraic problem.

(h^2  -  h^2) -p(h+h)

= (h - h)(h + h) -p(h+h)

= (h + h)(h - h - p) . The final solution provided by the book.kiss

Last edited by EbenezerSon (2013-07-09 00:23:57)

#12 2013-07-09 00:26:09

bobbym
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Re: Algebraic problem.

Hi;

That is an extremely weird answer they give.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#13 2013-07-09 00:33:55

EbenezerSon
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Re: Algebraic problem.

bobbym wrote:

Hi;

That is an extremely weird answer they give.

Sir, forgive me I should have provided how the question should be solved. the question says:

(The factorize the expression completely). I think it should be the answer if we are to factorize it,  I have now comprehended it.  And I can explain.

What do you say.

Last edited by EbenezerSon (2013-07-09 00:35:24)

#14 2013-07-09 00:41:06

bobbym
Administrator

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Re: Algebraic problem.

Hi;

If you now understand what they did then that is okay with me.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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