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## #1 2006-02-14 18:58:23

Titus
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### Perpendicular Lines

From the equation 3y = 5 - x

how do you find the gradient? and what is it?

thanks

## #2 2006-02-14 19:19:37

kempos
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### Re: Perpendicular Lines

y = (5 - x)/3

equation of a straight line: y = ax + b where a is a gradient.

## #3 2006-02-15 15:19:55

John E. Franklin
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### Re: Perpendicular Lines

If you are looking for the slant of the line perpendicular to this line, then it is negative one over slope of this line.
The slant of a line is the same anywhere on the line.
This is not true for a more complicated curve.  So the slope of the perpendicular line to this one is
three.

Imagine for a moment that even an earthworm may possess a love of self and a love of others.

## #4 2006-02-17 09:42:10

rp_
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### Re: Perpendicular Lines

ie. Sometimes its easier to understand when you see the formula

if the line gradient is ½ the the gradient of a perpendicular line will be -(1/(½) = -2

therefore in general the line with gradient m will have a pependicular line with gradient -1/m.

Last edited by rp_ (2006-02-17 09:42:29)