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#1 2006-02-14 18:58:23

Titus
Member

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Perpendicular Lines

From the equation 3y = 5 - x

how do you find the gradient? and what is it?

thanks

#2 2006-02-14 19:19:37

kempos
Full Member

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Re: Perpendicular Lines

y = (5 - x)/3

gradient = -1/3

equation of a straight line: y = ax + b where a is a gradient.

#3 2006-02-15 15:19:55

John E. Franklin
Star Member

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Re: Perpendicular Lines

If you are looking for the slant of the line perpendicular to this line, then it is negative one over slope of this line.
The slant of a line is the same anywhere on the line.
This is not true for a more complicated curve.  So the slope of the perpendicular line to this one is
three.


igloo myrtilles fourmis

#4 2006-02-17 09:42:10

rp_
Novice

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Re: Perpendicular Lines

ie. Sometimes its easier to understand when you see the formula

if the line gradient is the the gradient of a perpendicular line will be -(1/() = -2

therefore in general the line with gradient m will have a pependicular line with gradient -1/m.

Last edited by rp_ (2006-02-17 09:42:29)

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