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**Titus****Member**- Registered: 2005-03-07
- Posts: 10

From the equation 3y = 5 - x

how do you find the gradient? and what is it?

thanks

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**kempos****Member**- Registered: 2006-01-07
- Posts: 77

y = (5 - x)/3

gradient = -1/3

equation of a straight line: y = ax + b where a is a gradient.

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**John E. Franklin****Member**- Registered: 2005-08-29
- Posts: 3,562

If you are looking for the slant of the line perpendicular to this line, then it is negative one over slope of this line.

The slant of a line is the same anywhere on the line.

This is not true for a more complicated curve. So the slope of the perpendicular line to this one is

three.

**igloo** **myrtilles** **fourmis**

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**rp_****Member**- Registered: 2006-02-10
- Posts: 7

ie. Sometimes its easier to understand when you see the formula

if the line gradient is ½ the the gradient of a perpendicular line will be -(1/(½) = -2

therefore in general the line with gradient m will have a pependicular line with gradient -1/m.

*Last edited by rp_ (2006-02-16 10:42:29)*

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