Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

The problem with me is that I don't know how I will replace the vectors by which values?

The problem is attached in as an image.

*Last edited by Omareg94 (2013-05-06 11:26:49)*

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 106,381

Hi Omareg94;

Please provide the image?!

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

Offline

**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

Post updated. Please enable me to include links in my posts to be able to add images quickly.. Thanks!

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 106,381

Hi Omareg94;

I am unable to do that. The rule about no links until you are a member and have been here a while is a forum rule. You will have to provide a link to the image as you have done in post #1.

What is the circle with a dot inside mean?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

Offline

**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

Ok. No problem!

The circle with a dot inside means; scalar product

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 106,381

Hi;

Oh okay, you mean the dot product

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

Offline

**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

Yes, i mean the dot product

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 106,381

Any more drawings that you need to upload?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

Offline

**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

I solved it that way but I am not sure if I have did something wrong

*Last edited by Omareg94 (2013-05-06 13:17:48)*

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 106,381

Hi;

That drawing is not coming in very well for me. What did you get for 1?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

Offline

**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

100 from a.b=abcosθ

I suggested that a=10 as the side length of the square equal 10cm, is that ok?

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 106,381

I did it another way and got 100.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

Offline

**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

I think both are ok but I need someone to confirm my answer.. Let's wait

Thanks for your efforts!

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 106,381

The magnitudes are 10 so the formula is just plug in but yes wait for the vector people to show up.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

Offline

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,706

Hi Omar,

I've been out all day in the big city. Just got back.

1, 2, 3 and 6 look ok to me.

4 and 5 ? Two ways to do these:

(i) Magnitude of vector 1 x magnitude of vector 2 x cosine of angle between. You don't appear to have the right magnitudes for the diagonals.

(ii) Split the diagonals into two components, and do the scalar product of each, adding the results together. Same answer either way.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

Oh yes,, I see that magnitudes of diagonals in 4 and 5 are wrong it must be 10√2 not 10

Thanld a lot!

Offline

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,706

Correct.

If you want to post new answers, I'll check them for you.

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

Pages: **1**