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**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

The problem with me is that I don't know how I will replace the vectors by which values?

The problem is attached in as an image.

*Last edited by Omareg94 (2013-05-06 11:26:49)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 95,940

Hi Omareg94;

Please provide the image?!

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**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

Post updated. Please enable me to include links in my posts to be able to add images quickly.. Thanks!

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 95,940

Hi Omareg94;

I am unable to do that. The rule about no links until you are a member and have been here a while is a forum rule. You will have to provide a link to the image as you have done in post #1.

What is the circle with a dot inside mean?

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**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

Ok. No problem!

The circle with a dot inside means; scalar product

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 95,940

Hi;

Oh okay, you mean the dot product

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**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

Yes, i mean the dot product

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 95,940

Any more drawings that you need to upload?

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**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

I solved it that way but I am not sure if I have did something wrong

*Last edited by Omareg94 (2013-05-06 13:17:48)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 95,940

Hi;

That drawing is not coming in very well for me. What did you get for 1?

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**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

100 from a.b=abcosθ

I suggested that a=10 as the side length of the square equal 10cm, is that ok?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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I did it another way and got 100.

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**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

I think both are ok but I need someone to confirm my answer.. Let's wait

Thanks for your efforts!

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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The magnitudes are 10 so the formula is just plug in but yes wait for the vector people to show up.

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,017

Hi Omar,

I've been out all day in the big city. Just got back.

1, 2, 3 and 6 look ok to me.

4 and 5 ? Two ways to do these:

(i) Magnitude of vector 1 x magnitude of vector 2 x cosine of angle between. You don't appear to have the right magnitudes for the diagonals.

(ii) Split the diagonals into two components, and do the scalar product of each, adding the results together. Same answer either way.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**Omareg94****Member**- Registered: 2013-04-26
- Posts: 13

Oh yes,, I see that magnitudes of diagonals in 4 and 5 are wrong it must be 10√2 not 10

Thanld a lot!

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,017

Correct.

If you want to post new answers, I'll check them for you.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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