hi apiece

Welcome to the forum.

g(x)=2-5f(3x)

OK. I get that.

f'^(-1)(0)=5

Do you  mean the inverse function for f evaluated at x = 0, is 5  ?

The second image doesn't say this.

g'^(-1)(2)=?

Do you mean differentiate g, construct the inverse function, then evaluate it at x = 2    ?

That's not what you've got in the third image.

And now I think about it, by writing function^-1 do you mean the inverse function at all, or the reciprocal function

eg.  does sin^-1 mean arcsin or 1/sin ?

Bob

Last edited by bob bundy (2013-03-21 05:21:45)