Help me to solve this plz!
g(x)=2-5f(3x) & f'^(-1)(0)=5
Welcome to the forum.
OK. I get that.
Do you mean the inverse function for f evaluated at x = 0, is 5 ?
The second image doesn't say this.
Do you mean differentiate g, construct the inverse function, then evaluate it at x = 2 ?
That's not what you've got in the third image.
And now I think about it, by writing function^-1 do you mean the inverse function at all, or the reciprocal function
eg. does sin^-1 mean arcsin or 1/sin ?
Last edited by bob bundy (2013-03-20 06:21:45)
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