Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**apiece****Member**- Registered: 2013-03-20
- Posts: 1

Help me to solve this plz!

If

g(x)=2-5f(3x) & f'^(-1)(0)=5

g'^(-1)(2)=?

A)-0.33

B)0.66

C)0.33

D)-0.66

tnx

Offline

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,020

hi apiece

Welcome to the forum.

g(x)=2-5f(3x)

OK. I get that.

f'^(-1)(0)=5

Do you mean the inverse function for f evaluated at x = 0, is 5 ?

The second image doesn't say this.

g'^(-1)(2)=?

Do you mean differentiate g, construct the inverse function, then evaluate it at x = 2 ?

That's not what you've got in the third image.

And now I think about it, by writing function^-1 do you mean the inverse function at all, or the reciprocal function

eg. does sin^-1 mean arcsin or 1/sin ?

Bob

*Last edited by bob bundy (2013-03-20 06:21:45)*

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

Pages: **1**