Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2013-03-20 04:20:00

apiece
Member
Registered: 2013-03-20
Posts: 1

Help me to solve this plz!

Help me to solve this plz!
If
g(x)=2-5f(3x) & f'^(-1)(0)=5

g'^(-1)(2)=?

A)-0.33
B)0.66
C)0.33
D)-0.66
tnx

View Image: 1.gif View Image: 2.gif View Image: gif.gif

Offline

#2 2013-03-20 05:32:19

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,469

Re: Help me to solve this plz!

hi apiece

Welcome to the forum.

g(x)=2-5f(3x)

OK. I get that.

f'^(-1)(0)=5

Do you  mean the inverse function for f evaluated at x = 0, is 5  ?

The second image doesn't say this.

g'^(-1)(2)=?

Do you mean differentiate g, construct the inverse function, then evaluate it at x = 2    ?

That's not what you've got in the third image.

And now I think about it, by writing function^-1 do you mean the inverse function at all, or the reciprocal function

eg.  does sin^-1 mean arcsin or 1/sin ?

Bob

Last edited by bob bundy (2013-03-20 06:21:45)


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

Offline

Board footer

Powered by FluxBB