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AB and CD are two parallel chords in the same circle measuring 5 cm and 11 cm respectively.

If, the distance between AB and CD is 6 cm

Then find out the radius of the circle

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

'Humanity is still kept intact. It remains within.' -Alokananda

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How to solve?

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

'Humanity is still kept intact. It remains within.' -Alokananda

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,269

See diagram.

The perpendicular bisector of any chord goes through the centre of the circle (prove by congruency) and as the chords are parallel , FGE is a straight line.

So FG = x => GE = 6 - x

Get expressions for R using Pythagoras on AFG and also CEG.

Eliminate x and find R

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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Thanks I can do it now

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

'Humanity is still kept intact. It remains within.' -Alokananda

Offline

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