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AB and CD are two parallel chords in the same circle measuring 5 cm and 11 cm respectively.

If, the distance between AB and CD is 6 cm

Then find out the radius of the circle

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'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

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How to solve?

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,842

See diagram.

The perpendicular bisector of any chord goes through the centre of the circle (prove by congruency) and as the chords are parallel , FGE is a straight line.

So FG = x => GE = 6 - x

Get expressions for R using Pythagoras on AFG and also CEG.

Eliminate x and find R

Bob

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Thanks I can do it now

'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'

'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'

I'm not crazy, my mother had me tested.

Offline

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