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You are not logged in. Pages: 1 #1 20130303 09:34:58
Sigma notation and its application to binomials with exponentsHi #2 20130303 10:22:18
Re: Sigma notation and its application to binomials with exponentsHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #3 20130303 10:28:10
Re: Sigma notation and its application to binomials with exponentsHi bobbym Last edited by anonimnystefy (20130303 10:29:42) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #4 20130303 10:29:23
Re: Sigma notation and its application to binomials with exponentsShouldn't that be 4x^3? In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #5 20130303 10:30:35
Re: Sigma notation and its application to binomials with exponentsYou should really wait till I edit the post, which I have now done. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #6 20130303 10:37:37
Re: Sigma notation and its application to binomials with exponentsOkay, hope you are right! In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. Pages: 1 