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•  » Sigma notation and its application to binomials with exponents

## #1 2013-03-03 09:34:58

Winx89
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### Sigma notation and its application to binomials with exponents

Hi

I have a certain problem that I hope you can help me out with it is a binomial like in the examples however the internal terms already have exponents. (4x3-1/root x)8. Sorry not very clear, tablet has limited keyboard but in words, open bracket four x to the power of three minus one over the square root of x, closed bracket to the power of eight. They are asking for the coefficient of the xterm to the power of 3, 5 and 10 respectively.

## #2 2013-03-03 10:22:18

bobbym

Online

### Re: Sigma notation and its application to binomials with exponents

Hi;

Is this what you are talking about?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #3 2013-03-03 10:28:10

anonimnystefy
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### Re: Sigma notation and its application to binomials with exponents

Hi bobbym

I think it's

inside the brackets.

Last edited by anonimnystefy (2013-03-03 10:29:42)

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #4 2013-03-03 10:29:23

bobbym

Online

### Re: Sigma notation and its application to binomials with exponents

Shouldn't that be 4x^3?

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #5 2013-03-03 10:30:35

anonimnystefy
Real Member

Offline

### Re: Sigma notation and its application to binomials with exponents

You should really wait till I edit the post, which I have now done.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #6 2013-03-03 10:37:37

bobbym

Online

### Re: Sigma notation and its application to binomials with exponents

Okay, hope you are right!

Coefficient of x^3 is 448

Coefficient of x^5 is 0

Coefficient of x^10 is 17920

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
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