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You are not logged in. #4 20130217 21:26:10
Re: integrate (1+2e^xe^(x)^(1)Your substitution will work just fine if you use the fact that the integral of 1/(a^2 + x^2) = (1/a)arctan(x/a). #6 20130218 08:02:13
Re: integrate (1+2e^xe^(x)^(1)You have a quadratic form in your denominator, what can you do about that? #8 20130218 11:15:20
Re: integrate (1+2e^xe^(x)^(1)You could complete the square in the denominator. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #10 20130218 12:21:35
Re: integrate (1+2e^xe^(x)^(1)You get it to the form (a*x+b)^2+c. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #12 20130219 10:38:34
Re: integrate (1+2e^xe^(x)^(1)Of course, I am just showing that it can also be done as zf. suggested. The partial fractions work better in this integral. Last edited by anonimnystefy (20130219 10:43:46) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment 