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#4 2013-02-17 21:26:10
- zetafunc.
- Guest
Re: integrate (1+2e^x-e^(-x)^(-1)
Your substitution will work just fine if you use the fact that the integral of 1/(a^2 + x^2) = (1/a)arctan(x/a).
#6 2013-02-18 08:02:13
- zetafunc.
- Guest
Re: integrate (1+2e^x-e^(-x)^(-1)
You have a quadratic form in your denominator, what can you do about that?
#8 2013-02-18 11:15:20
- anonimnystefy
- Real Member
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Re: integrate (1+2e^x-e^(-x)^(-1)
You could complete the square in the denominator.
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón
#10 2013-02-18 12:21:35
- anonimnystefy
- Real Member
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Re: integrate (1+2e^x-e^(-x)^(-1)
You get it to the form (a*x+b)^2+c.
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón
#12 2013-02-19 10:38:34
- anonimnystefy
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Re: integrate (1+2e^x-e^(-x)^(-1)
Of course, I am just showing that it can also be done as zf. suggested. The partial fractions work better in this integral.
Last edited by anonimnystefy (2013-02-19 10:43:46)
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón