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#1 2013-02-16 13:29:20

{7/3}
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P-norm

The p-norm of a vector(in 2d) is (|x|^p+|y|^p)^(1/p) my question is can p be 0,fraction or nagetive?


There are 10 kinds of people in the world,people who understand binary and people who don't.

#2 2013-02-16 19:12:47

zetafunc.
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Re: P-norm

If I recall correctly, p can be any real number apart from 0.

#3 2013-02-16 19:28:17

anonimnystefy
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Re: P-norm

Actually, p must be a real number greater or equal to 1.


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#4 2013-02-16 22:54:13

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Re: P-norm

Why isn't nagetive number or fractions<1 allowed?


There are 10 kinds of people in the world,people who understand binary and people who don't.

#5 2013-02-17 05:54:15

anonimnystefy
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Re: P-norm

Because it wouldn't be a norm (it would give zero values if any of the coordinates is 0).


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#6 2013-02-17 15:16:18

{7/3}
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Re: P-norm

Oh,thanks.


There are 10 kinds of people in the world,people who understand binary and people who don't.

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