Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

**{7/3}****Member**- Registered: 2013-02-11
- Posts: 210

The p-norm of a vector(in 2d) is (|x|^p+|y|^p)^(1/p) my question is can p be 0,fraction or nagetive?

There are 10 kinds of people in the world,people who understand binary and people who don't.

Offline

**zetafunc.****Guest**

If I recall correctly, p can be any real number apart from 0.

**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,796

Actually, p must be a real number greater or equal to 1.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

The knowledge of some things as a function of age is a delta function.

Offline

**{7/3}****Member**- Registered: 2013-02-11
- Posts: 210

Why isn't nagetive number or fractions<1 allowed?

There are 10 kinds of people in the world,people who understand binary and people who don't.

Offline

**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,796

Because it wouldn't be a norm (it would give zero values if any of the coordinates is 0).

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

The knowledge of some things as a function of age is a delta function.

Offline

**{7/3}****Member**- Registered: 2013-02-11
- Posts: 210

Oh,thanks.

There are 10 kinds of people in the world,people who understand binary and people who don't.

Offline