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## #1 2012-12-23 02:05:31

BarandaMan
Guest

### How to rearrange this?

Why does

((Pt)^(n-1))((Pi)^(1-n)) EQUAL the term ((Pi/Pt)^(1-n))? Apparantly these two are equivalent? I am not good at rearranging / how to change the signs on powers etc, can someone explain?

Thanks

## #2 2012-12-23 07:36:56

muxdemux
Member
Registered: 2012-12-23
Posts: 80

### Re: How to rearrange this?

I just wrote

then did a bunch of algebra. Some things to remember while working it out:

and

Good luck!

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## #3 2012-12-23 14:56:03

BarandaMan
Guest

### Re: How to rearrange this?

muxdemux wrote:

I just wrote

then did a bunch of algebra. Some things to remember while working it out:

and

Good luck!

Thank you! So based on the first rule you said, then (Pi/Pt)^(1-n) = (Pi^(1-n)(Pt)^(1-n)...which isn't the answer. Can you help??

## #4 2012-12-23 16:13:01

muxdemux
Member
Registered: 2012-12-23
Posts: 80

### Re: How to rearrange this?

That's a start! Once you've got that, you should divide both sides by

Notice that

and you should be able to use that second rule I gave you.

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