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**jackme12****Member**- Registered: 2012-12-17
- Posts: 6

As the subject says, can anybody prove that route 5 is irrational?

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,600

Let's assume that the opposite is true, that is that square root 5 is rational. This would mean it can be written in the form p/q, where gcd(p,q)=1.

So:

sqrt(5)=p/q

Then we square both sides:

5=p^2/q^2

5*q^2=p^2

So this means that p must be divisible by 5, and we can write p=5*r and our equation becomes:

5*q^2=25*r^2

q^2=5*r^2,

But this would mean that q is also divisible by 5, and we said that p and q have a gcd of 1! This is a contradiction, so our initial assumption that sqrt(5) is rational is false!

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,466

hi Stefy,

He posted again in help and I replied there.

If p^2 is divisible by 5, how do you know that p is also divisible by 5 ?

(I know it is, but I want a justification please. Otherwise every root is irrational.)

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,600

If p weren't divisible by 5 then neither would be p^2.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,466

why?

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,600

This can be shown by assuming that p isn't divisible by 5 and then going through 4 cases p=5k+1,5k+2,5k+3,5k+4 and squaring p in each case to see that the square of p is respectively 1, 4, 4, 1 in each case.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,466

Ok. That'll do me. Thanks.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,600

Don't mention it!

Here lies the reader who will never open this book. He is forever dead.

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**jackme12****Member**- Registered: 2012-12-17
- Posts: 6

Thanks a lot, that is great help.

Apologies about the confusion with posting in two forums.

Jack

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,600

You're welome!

Here lies the reader who will never open this book. He is forever dead.

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**mathaholic****Member**- From: Juliania
- Registered: 2012-11-29
- Posts: 2,870
- Website

Jackme12, welcome to the forum. Sorry if I was a bit late in greeting ya. Anyways, I cannot prove yet that route 5 is irrational 'cause I am just too young to learn irrational numbers like those.

Have fun in the forum, Jackme12!

Julian

"What is the square root of 2? 1.4141592653589793238" Seriously, I thought it was that. Too round?

3.141592653589793238...

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