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You are not logged in. #2 20121128 22:41:01
Re: factoring polynomialshi deiv You can simplify the problem by making the substitution Then it becomes I notice that x = 1 makes this expression zero, so by the factor theorem (x + 1) is a factor. From there you can easily get the quadratic that goes with this and you'll find the formula will give another two factors. Then you can go back to the m expression from there. Bob You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #3 20121128 23:19:05
Re: factoring polynomialsHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #4 20121128 23:34:45
Re: factoring polynomialsHow about this one? What are the factors of: #6 20121129 00:30:59
Re: factoring polynomialsI think you are going to find that is irreducible in Q and therefore in Z. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 