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#2 2012-11-28 22:41:01
- bob bundy
- Moderator
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Re: factoring polynomials
hi deiv
Welcome to the forum.
You can simplify the problem by making the substitution
Then it becomes
I notice that x = -1 makes this expression zero, so by the factor theorem (x + 1) is a factor.
From there you can easily get the quadratic that goes with this and you'll find the formula will give another two factors.
Then you can go back to the m expression from there.
Bob
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
#3 2012-11-28 23:19:05
- bobbym
- Administrator
Online
Re: factoring polynomials
Hi;
Or take it over to Wolfram.
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#4 2012-11-28 23:34:45
- deiv
- Guest
Re: factoring polynomials
How about this one? What are the factors of:
3x(x+2y) + 4y(3x+2y)
#6 2012-11-29 00:30:59
- bobbym
- Administrator
Online
Re: factoring polynomials
I think you are going to find that is irreducible in Q and therefore in Z.
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.