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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

This needs to be simplified. I need the work and answer.

THANKS A TON!!

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi SlowlyFading;

If you saw the problem I worked through in the previous post then you should have some idea how to do this. In fact this one is easier than that one.

What is on the top that is the exact same as what is on the bottom? Then you can cross them out. Give it a try.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

I have a very slight idea of how to do these.. Barely. I'm very bad with these type of problems.

Could I have the work for this problem?

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Do you see the (2x-3) expression? They even have bracketed it for you. Let's start right there.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

I need to simplify it? By adding those terms together?

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi SlowlyFading;

One step at a time. Take and cross out on the top and bottom every occurrence (2x-3). What do you get? Please give it a try.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

I don't know how to do that..

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi;

Write the problem on a piece of paper and cross out each (2x-3) as I have done below.

Now just take what is left after you replace each crossed out (2x-3) with a 1

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

So,

It would become

I'm just here to get some help with an online math course I'm taking.

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

?

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi SlowlyFading;

If you replace the first (2x-3) that is crossed out by a 1 you would get.

You try the next one.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

So,

Except the "3" should be the first number in the equation.

I'm just here to get some help with an online math course I'm taking.

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

I really don't know how to do this as you can see.

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

That is okay, I will show you how.

You replace the

with a one. I have done the next part

you try the last part.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

So,

I don't know how to insert that dot you have in your posts so I just slept out "dot" instead

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi;

Yes, that is correct! Can you simplify a little bit more?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

?

I'm just here to get some help with an online math course I'm taking.

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

That second "dot" wasn't meant to be there, my bad.

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi;

That is not quite correct.

Let's look at this again. 3 * 1 = 3. What does x * 1 equal?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

becomes

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi;

That is correct, now there is one more bit of simplification.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

?

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi;

Not quite. You have ( 3 - x ) over one. What does anything over one equal?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**SlowlyFading****Member**- Registered: 2012-06-12
- Posts: 149

?

I'm just here to get some help with an online math course I'm taking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,238

Hi;

Not quite. You have ( 3 - x ) over one. Where did the x go?

If

Then what does

equal?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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