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#1 2006-01-08 05:48:18
- pamela
- Guest
'natural' log
i seem to have a problem with logs.
the question i cant seem to get to terms with is:
simplify
log64 - log128 + log 32 + log256
help appreciated
#2 2006-01-08 06:08:57
- irspow
- Member
- Registered: 2005-11-24
- Posts: 1,055
Re: 'natural' log
Whenever you see a log a + log b it says the same thing as log (ab). And whenever you see log a - log b it is the same as log (a/b).
So log 64 - log 128 = log (64/128) and log 32 + log 256 = log (256×32)
Now you have [log (64/128)] + [log (256×32)]
This then reduces to log [(64/128)(256×32)]
log 4096 ≈ 3.61236
Last edited by irspow (2006-01-08 08:52:14)
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