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#1 2006-01-08 05:48:18

pamela
Guest

'natural' log

i seem to have a problem with logs.

the question i cant seem to get to terms with is:

simplify

log64 - log128 + log 32 + log256

help appreciated

#2 2006-01-08 06:08:57

irspow
Member
Registered: 2005-11-24
Posts: 455

Re: 'natural' log

Whenever you see a log a + log b it says the same thing as log (ab).   And whenever you see log a - log b it is the same as log (a/b).

  So log 64 - log 128 = log (64/128) and log 32 + log 256 = log (256×32)

  Now you have [log (64/128)] + [log (256×32)]

  This then reduces to log [(64/128)(256×32)]

  log 4096 ≈ 3.61236

Last edited by irspow (2006-01-08 08:52:14)

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