Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

Is it a turkey?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

Offline

**Sumasoltin****Member**- Registered: 2012-04-28
- Posts: 30

Aha! I learnt an American created the"Batman equation" in China.Did you hear about anything about it?

Offline

**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,886

It's mayo! Or mustard?

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

Offline

**Sumasoltin****Member**- Registered: 2012-04-28
- Posts: 30

A leg of turkey exactly!

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

The Batman equation?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

Offline

**Sumasoltin****Member**- Registered: 2012-04-28
- Posts: 30

See it here:w w w.howtogeek.com/106221/stupid-geek-tricks-how-to-plot-the-batman-curve-in-google-search/

Well , math is a subject created by God, and you can make any thing into equations if you want. Pencils, flowers, waves, boats, mountains, bra and math(:P),and even a girl !

*Last edited by Sumasoltin (2012-04-30 01:49:00)*

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

I got it, thanks for the info.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

Offline

**benice****Member**- Registered: 2010-06-10
- Posts: 110

My Gallery of Math Art: benice equation

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,251

Hi benice;

Thanks for coming over. Thanks for the link too.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**Sumasoltin****Member**- Registered: 2012-04-28
- Posts: 30

benice wrote:

bobbym wrote:The Batman equation?

Hi bobbym,

The original post is here.

Hi,benice;

I review the sites and infer that the earliest one is before 2011-07-29 09:35:26 (+8). But the site you gave just show "9 months ago", when the equation was flooding, so I don't know whether that is the original one.

We tried to plot it, only to found it abused "sqrt" so there is no plot. I tried to correct but gave up later because of the complex numbers (complex, not "i").

*Last edited by Sumasoltin (2012-05-02 12:07:33)*

Offline

**benice****Member**- Registered: 2010-06-10
- Posts: 110

Sumasoltin wrote:

Hi,benice;

I review the sites and infer that the earliest one is before 2011-07-29 09:35:26 (+8). But the site you gave just show "9 months ago", when the equation was flooding, so I don't know whether that is the original one.

The original post was submitted on 28 Jul 2011. (Look at the upper right corner of the comment page.)

Sumasoltin wrote:

We tried to plot it, only to found it abused "sqrt" so there is no plot. I tried to correct but gave up later because of the complex numbers (complex, not "i").

Plot each component separately:

f1(x,y) = ((x/7)^2) * sqrt( sign(abs(x)-3) ) + ((y/3)^2) * sqrt( sign(y+3*sqrt(33)/7) ) - 1

f2(x,y) = abs(x/2) - ((3*sqrt(33)-7)/112)*(x^2) - 3 + sqrt(1 - (abs(abs(x)-2)-1)^2) - y

f3(x,y) = 9*sqrt( sign((1-abs(x))*(abs(x)-0.75)) ) - 8*abs(x) - y

f4(x,y) = 3*abs(x) + 0.75*sqrt( sign((0.75-abs(x))*(abs(x)-0.5)) ) - y

f5(x,y) = 2.25*sqrt( sign((0.5-abs(x))*(abs(x)+0.5)) ) - y

f6(x,y) = 6*sqrt(10)/7 + (1.5-0.5*abs(x))*sqrt(sign(abs(x)-1)) - 6*(sqrt(10)/14)*sqrt(4-(abs(x)-1)^2) - y

My Gallery of Math Art: benice equation

Offline