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#26 2012-04-30 23:30:24
- bobbym
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Re: Find an equation showing special graph
Is it a turkey?
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#27 2012-04-30 23:33:53
- Sumasoltin
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Re: Find an equation showing special graph
Aha! I learnt an American created the"Batman equation" in China.Did you hear about anything about it?
#28 2012-04-30 23:33:57
- anonimnystefy
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Re: Find an equation showing special graph
It's mayo! Or mustard?
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón
#30 2012-04-30 23:36:27
- bobbym
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Re: Find an equation showing special graph
The Batman equation?
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#31 2012-04-30 23:42:28
- Sumasoltin
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Re: Find an equation showing special graph
See it here:w w w.howtogeek.com/106221/stupid-geek-tricks-how-to-plot-the-batman-curve-in-google-search/
Well , math is a subject created by God, and you can make any thing into equations if you want. Pencils, flowers, waves, boats, mountains, bra and math(
),and even a girl !
Last edited by Sumasoltin (2012-04-30 23:49:00)
#32 2012-04-30 23:45:35
- bobbym
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Re: Find an equation showing special graph
I got it, thanks for the info.
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#33 2012-05-03 02:47:08
- benice
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Re: Find an equation showing special graph
bobbym wrote:
The Batman equation?
Hi bobbym,
The original post is here: http://redd.it/j2qjc.
My Gallery of Math Art: benice equation
#34 2012-05-03 05:48:24
- bobbym
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Re: Find an equation showing special graph
Hi benice;
Thanks for coming over. Thanks for the link too.
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#35 2012-05-03 10:06:05
- Sumasoltin
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Re: Find an equation showing special graph
benice wrote:
bobbym wrote:
The Batman equation?
Hi bobbym,
The original post is here.
Hi,benice;
I review the sites and infer that the earliest one is before 2011-07-29 09:35:26 (+8). But the site you gave just show "9 months ago", when the equation was flooding, so I don't know whether that is the original one.
We tried to plot it, only to found it abused "sqrt" so there is no plot. I tried to correct but gave up later because of the complex numbers (complex, not "i").
Last edited by Sumasoltin (2012-05-03 10:07:33)
#36 2012-05-03 12:27:17
- benice
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Re: Find an equation showing special graph
Sumasoltin wrote:
Hi,benice;
I review the sites and infer that the earliest one is before 2011-07-29 09:35:26 (+8). But the site you gave just show "9 months ago", when the equation was flooding, so I don't know whether that is the original one.
The original post was submitted on 28 Jul 2011. (Look at the upper right corner of the comment page.)
Sumasoltin wrote:
We tried to plot it, only to found it abused "sqrt" so there is no plot. I tried to correct but gave up later because of the complex numbers (complex, not "i").
Plot each component separately:
f1(x,y) = ((x/7)^2) * sqrt( sign(abs(x)-3) ) + ((y/3)^2) * sqrt( sign(y+3*sqrt(33)/7) ) - 1
f2(x,y) = abs(x/2) - ((3*sqrt(33)-7)/112)*(x^2) - 3 + sqrt(1 - (abs(abs(x)-2)-1)^2) - y
f3(x,y) = 9*sqrt( sign((1-abs(x))*(abs(x)-0.75)) ) - 8*abs(x) - y
f4(x,y) = 3*abs(x) + 0.75*sqrt( sign((0.75-abs(x))*(abs(x)-0.5)) ) - y
f5(x,y) = 2.25*sqrt( sign((0.5-abs(x))*(abs(x)+0.5)) ) - y
f6(x,y) = 6*sqrt(10)/7 + (1.5-0.5*abs(x))*sqrt(sign(abs(x)-1)) - 6*(sqrt(10)/14)*sqrt(4-(abs(x)-1)^2) - y
My Gallery of Math Art: benice equation