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**Flowers4Carlos****Member**- Registered: 2005-08-25
- Posts: 106

i have a quick question regarding the unit normal vector on the following integral:

∫∫FdS = ∫∫FndS

s s

if the surface S is given by z=g(x,y) then the unit normal vector is f(x,y,z)= z - g(x,y) ⇒

gradf(x,y,z)

n= -----------------

|gradf(x,y,z)|

my question is if i'm given the surface 3z=g(x,y), then what should the unit normal vector be???

is it f(x,y,z) = 3z - g(x,y) or f(x,y,z) = z - g(x,y)/3

*Last edited by Flowers4Carlos (2005-12-19 22:21:43)*

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**austin81****Member**- Registered: 2005-03-21
- Posts: 39

In my opinion I do think (x,y,z) = [z - g(x,y)]/3 is coorect.Since we shall be integrating

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**austin81****Member**- Registered: 2005-03-21
- Posts: 39

I'm not very sure of that.

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