i have a quick question regarding the unit normal vector on the following integral:
∫∫FdS = ∫∫FndS
if the surface S is given by z=g(x,y) then the unit normal vector is f(x,y,z)= z - g(x,y) ⇒
my question is if i'm given the surface 3z=g(x,y), then what should the unit normal vector be???
is it f(x,y,z) = 3z - g(x,y) or f(x,y,z) = z - g(x,y)/3
Last edited by Flowers4Carlos (2005-12-19 22:21:43)
In my opinion I do think (x,y,z) = [z - g(x,y)]/3 is coorect.Since we shall be integrating