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**reconsideryouranswer****Member**- Registered: 2011-05-11
- Posts: 171

From:

http://www.mathsisfun.com/sets/function-inverse.html

"Not Always Solvable!

It is sometimes not possible to find an Inverse of a Function.

Example: f(x) = x/2 + sin(x)

We cannot work out the inverse of this, because we cannot solve for "x":

y = x/2 + sin(x)

y ... ? = x"

This function isn't even one-to-one, so by default, a person cannot

find an inverse for it, because the inverse does not exist for it.

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Also, you could mention that certain functions are inverses of themselves.

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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,659

But we can easily choose an interval where it is one-to-one, say [0,2]. Is it then solvable?

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