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#1 2011-11-26 17:38:20
- reconsideryouranswer
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Issues with the inverse functions page
From:
http://www.mathsisfun.com/sets/function-inverse.html
"Not Always Solvable!
It is sometimes not possible to find an Inverse of a Function.
Example: f(x) = x/2 + sin(x)
We cannot work out the inverse of this, because we cannot solve for "x":
y = x/2 + sin(x)
y ... ? = x"
This function isn't even one-to-one, so by default, a person cannot
find an inverse for it, because the inverse does not exist for it.
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Also, you could mention that certain functions are inverses of themselves.
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#2 2011-11-27 09:16:25
- MathsIsFun
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Re: Issues with the inverse functions page
But we can easily choose an interval where it is one-to-one, say [0,2]. Is it then solvable?
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman