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•  » Indefinite integral involving a logarithm - - I am quizzing users...

## #1 2011-08-09 04:00:22

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### Indefinite integral involving a logarithm - - I am quizzing users...

this.

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## #2 2011-08-09 04:07:31

anonimnystefy
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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

Last edited by anonimnystefy (2011-08-09 04:58:46)

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #3 2011-08-09 04:18:46

bobbym

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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #4 2011-08-09 04:54:06

anonimnystefy
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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #5 2011-08-09 04:56:01

bobbym

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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

Hi;

Yes, you should.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #6 2011-08-09 07:33:47

anonimnystefy
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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

what is the purpose of this topic?

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #7 2011-08-09 07:39:35

bobbym

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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

It says up there to quiz the users.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #8 2011-08-09 07:43:20

anonimnystefy
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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

so there will be more questions? it says indefinite 'integral'

or is this connected to the log(x) , ln(x) argument from the other topic.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #9 2011-08-09 07:45:20

bobbym

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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

That was a different integral.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #10 2011-08-09 07:50:51

anonimnystefy
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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

yes but it is singular,so i am not sure if there is going to be more.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #11 2011-08-09 11:16:10

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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

this. Find the answer to this:

Signature line:

I wish a had a more interesting signature line.

## #12 2011-08-09 16:27:13

bobbym

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### Re: Indefinite integral involving a logarithm - - I am quizzing users...

Mathematicians, statisticians, and some engineers generally understand either "log(x)" or "ln(x)" to mean loge(x), i.e., the natural logarithm of x, and write "log10(x)" if the base 10 logarithm of x is intended.

http://en.wikipedia.org/wiki/Natural_logarithm

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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