Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

Login

Username

Password

Not registered yet?

  • Index
  •  » Exercises
  •  » Indefinite integral involving a logarithm - - I am quizzing users...

#1 2011-08-09 04:00:22

reconsideryouranswer
Full Member

Offline

Indefinite integral involving a logarithm - - I am quizzing users...

this.

Find the answer to this:




Signature line:

I wish a had a more interesting signature line.
 

#2 2011-08-09 04:07:31

anonimnystefy
Real Member

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

hi reconsideryouranswer

Last edited by anonimnystefy (2011-08-09 04:58:46)


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#3 2011-08-09 04:18:46

bobbym
Administrator

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

Hi reconsideryouranswer;


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#4 2011-08-09 04:54:06

anonimnystefy
Real Member

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

should i hide my answer?


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#5 2011-08-09 04:56:01

bobbym
Administrator

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

Hi;

Yes, you should.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#6 2011-08-09 07:33:47

anonimnystefy
Real Member

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

what is the purpose of this topic?


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#7 2011-08-09 07:39:35

bobbym
Administrator

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

It says up there to quiz the users.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#8 2011-08-09 07:43:20

anonimnystefy
Real Member

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

so there will be more questions? it says indefinite 'integral'

or is this connected to the log(x) , ln(x) argument from the other topic.


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#9 2011-08-09 07:45:20

bobbym
Administrator

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

That was a different integral.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#10 2011-08-09 07:50:51

anonimnystefy
Real Member

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

yes but it is singular,so i am not sure if there is going to be more.


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#11 2011-08-09 11:16:10

reconsideryouranswer
Full Member

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

reconsideryouranswer wrote:

this. Find the answer to this:








Signature line:

I wish a had a more interesting signature line.
 

#12 2011-08-09 16:27:13

bobbym
Administrator

Offline

Re: Indefinite integral involving a logarithm - - I am quizzing users...

Mathematicians, statisticians, and some engineers generally understand either "log(x)" or "ln(x)" to mean loge(x), i.e., the natural logarithm of x, and write "log10(x)" if the base 10 logarithm of x is intended.

Please check this page out. The part of notational convention clears it up.

http://en.wikipedia.org/wiki/Natural_logarithm


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 
  • Index
  •  » Exercises
  •  » Indefinite integral involving a logarithm - - I am quizzing users...

Board footer

Powered by FluxBB