Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
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You are not logged in. #1 2011-07-06 04:11:50
Question about a "closed walk" in a graphHi, #2 2011-07-06 06:03:00
Re: Question about a "closed walk" in a graphhi iwan_ccie Last edited by anonimnystefy (2011-07-06 06:03:41) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón #3 2011-07-06 07:01:59
Re: Question about a "closed walk" in a graphThanks for the answer ... #4 2011-07-06 07:10:48
Re: Question about a "closed walk" in a graphhi iwan_ccie The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón #5 2011-07-06 07:14:15
Re: Question about a "closed walk" in a graphSo it does not really matter how the walk goes in a closed walk... as long as the begin and end vertex are the same... Right? Last edited by iwan_ccie (2011-07-06 07:15:31) #6 2011-07-06 07:20:21
Re: Question about a "closed walk" in a graphyup. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón |