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You are not logged in. #1 20110706 04:11:50
Question about a "closed walk" in a graphHi, #2 20110706 06:03:00
Re: Question about a "closed walk" in a graphhi iwan_ccie Last edited by anonimnystefy (20110706 06:03:41) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #3 20110706 07:01:59
Re: Question about a "closed walk" in a graphThanks for the answer ... #4 20110706 07:10:48
Re: Question about a "closed walk" in a graphhi iwan_ccie The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #5 20110706 07:14:15
Re: Question about a "closed walk" in a graphSo it does not really matter how the walk goes in a closed walk... as long as the begin and end vertex are the same... Right? Last edited by iwan_ccie (20110706 07:15:31) #6 20110706 07:20:21
Re: Question about a "closed walk" in a graphyup. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment 