hi can someone explain in detail how to solve this kind of problem please:
1) 7*4^x = 5*9^x 2)log3 3 + log9 1
you should use logarithms to solve it, thx!
1) xlog4 + log7 = xlog9+ log5
xlog4 - xlog9 = log5 - log7
xlog9 - xlog4 = log7 - log5
x(log9 - log4) = log7 - log5
x = (log7 - log5)/(log9 - log4)
The second question isn't clear
Character is who you are when no one is looking.
I think that, on the second question, he means "log base 3 of 3 + log base 9 of 1".
If so, it's easy. 3¹ = 3, and 9^0 = 1. So, 1 + 0 = 1.
El que pega primero pega dos veces.