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## #1 2005-11-11 15:17:01

pman
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### need explaination

hi can someone explain in detail how to solve this kind of problem please:

#### Code:

``` 1)  7*4^x = 5*9^x

2)log3 3 + log9 1```

you should use logarithms to solve it, thx!

## #2 2005-11-11 15:27:49

ganesh
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### Re: need explaination

1) xlog4 + log7 = xlog9+ log5
xlog4 - xlog9 = log5 - log7
xlog9 - xlog4 = log7 - log5
x(log9 - log4) = log7 - log5
x = (log7 - log5)/(log9 - log4)

The second question isn't clear

Character is who you are when no one is looking.

## #3 2005-11-11 16:32:55

ryos
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### Re: need explaination

I think that, on the second question, he means "log base 3 of 3 + log base 9 of 1".

If so, it's easy. 3¹ = 3, and 9^0 = 1. So, 1 + 0 = 1.

El que pega primero pega dos veces.

pman
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thx alot guys

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